I have a String with an unknown length that looks something like this
"dog, cat, bear, elephant, ..., giraffe"
What would be the optimal way to divide this string at the commas so each word could become an element of an ArrayList?
For example
List<String> strings = new ArrayList<Strings>();
// Add the data here so strings.get(0) would be equal to "dog",
// strings.get(1) would be equal to "cat" and so forth.
You could do this:
String str = "...";
List<String> elephantList = Arrays.asList(str.split(","));
Basically the .split()
method will split the string according to (in this case) delimiter you are passing and will return an array of strings.
However, you seem to be after a List of Strings rather than an array, so the array must be turned into a list by using the Arrays.asList()
utility. Just as an FYI you could also do something like so:
String str = "...";
ArrayList<String> elephantList = (ArrayList<String>)Arrays.asList(str.split(","));
But it is usually better practice to program to an interface rather than to an actual concrete implementation, so I would recommend the 1st option.
.split
method is one of the most handy methods in the String class, I would recommend you check out the link for the JavaDocs I have included in my answer ;) - npinti 2012-05-17 07:52
str.split
accepts regex so you can use str.split(",[ ]*");
so you remove commas and spaces after commas - vertti 2013-10-31 08:38
new HashSet<String>(Arrays.asList(str.split(",")));
- npinti 2018-03-12 11:55
Well, you want to split, right?
String animals = "dog, cat, bear, elephant, giraffe";
String[] animalsArray = animals.split(",");
If you want to additionally get rid of whitespaces around items:
String[] animalsArray = animals.split("\\s*,\\s*");
Arrays.asList()
idiom - Tomasz Nurkiewicz 2012-05-17 07:47
You can split it and make an array then access like array
String names = "prappo,prince";
String[] namesList = names.split(",");
you can access like
String name1 = names[0];
String name2 = names[1];
or using loop
for(String name : namesList){
System.out.println(name);
}
hope it will help you .
A small improvement: above solutions will not remove leading or trailing spaces in the actual String. It's better to call trim before calling split. Instead of this,
String[] animalsArray = animals.split("\\s*,\\s*");
use
String[] animalsArray = animals.trim().split("\\s*,\\s*");
("\\s*,\\s*")
just use (",");
this will results same - W I Z A R D 2015-01-10 05:13
trim(" string, with , space ")
will be "string, with , space"
- Thomas Leduc 2015-05-13 08:08
"dog, cat, bear, elephant, giraffe"
then no need of trim()
and in ur case if use trim()
then out put will be "string,with,space"
not this "string, with , space"
W I Z A R D 2015-05-13 08:34
" string, with , space ".trim()
return "string, with , space"
. Like javadoc says : returns a copy of the string, with leading and trailing whitespace omitted.
You are wrong and @user872858 is right - Thomas Leduc 2015-05-13 08:55
First you can split names like this
String animals = "dog, cat, bear, elephant,giraffe";
String animals_list[] = animals.split(",");
to Access your animals
String animal1 = animals_list[0];
String animal2 = animals_list[1];
String animal3 = animals_list[2];
String animal4 = animals_list[3];
And also you want to remove white spaces and comma around animal names
String animals_list[] = animals.split("\\s*,\\s*");
For completeness, using the Guava library, you'd do: Splitter.on(",").split(“dog,cat,fox”)
Another example:
String animals = "dog,cat, bear,elephant , giraffe , zebra ,walrus";
List<String> l = Lists.newArrayList(Splitter.on(",").trimResults().split(animals));
// -> [dog, cat, bear, elephant, giraffe, zebra, walrus]
Splitter.split()
returns an Iterable, so if you need a List, wrap it in Lists.newArrayList()
as above. Otherwise just go with the Iterable, for example:
for (String animal : Splitter.on(",").trimResults().split(animals)) {
// ...
}
Note how trimResults()
handles all your trimming needs without having to tweak regexes for corner cases, as with String.split()
.
If your project uses Guava already, this should be your preferred solution. See Splitter documentation in Guava User Guide or the javadocs for more configuration options.
Can try with this worked for me
sg = sg.replaceAll(", $", "");
or else
if (sg.endsWith(",")) {
sg = sg.substring(0, sg.length() - 1);
}
Remove all white spaces and create an fixed-size or immutable List (See asList
API docs)
final String str = "dog, cat, bear, elephant, ..., giraffe";
List<String> list = Arrays.asList(str.replaceAll("\\s", "").split(","));
// result: [dog, cat, bear, elephant, ..., giraffe]
It is possible to also use replaceAll(\\s+", "")
but maximum efficiency depends on the use case. (see @GurselKoca answer to Removing whitespace from strings in Java)
You can use something like this:
String animals = "dog, cat, bear, elephant, giraffe";
List<String> animalList = Arrays.asList(animals.split(","));
Also, you'd include the libs:
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
Use this :
List<String> splitString = (List<String>) Arrays.asList(jobtype.split(","));
In Kotlin,
val stringArray = commasString.replace(", ", ",").split(",")
where stringArray
is List<String>
and commasString
is String
with commas and spaces
in build.gradle add Guava
compile group: 'com.google.guava', name: 'guava', version: '27.0-jre'
and then
public static List<String> splitByComma(String str) {
Iterable<String> split = Splitter.on(",")
.omitEmptyStrings()
.trimResults()
.split(str);
return Lists.newArrayList(split);
}
public static String joinWithComma(Set<String> words) {
return Joiner.on(", ").skipNulls().join(words);
}
enjoy :)
There is a function called replaceAll()
that can remove all whitespaces by replacing them with whatever you want. As an example
String str=" 15. 9 4;16.0 1"
String firstAndSecond[]=str.replaceAll("\\s","").split(";");
System.out.println("First:"+firstAndSecond[0]+", Second:"+firstAndSecond[1]);
will give you:
First:15.94, Second:16.01