How do you pass all the parameters of one function into another

function a(){
    arguments.length;// this is 1
    // how do I pass any parameter function a receives into another function
    b(what to put here?); // say pass all parameters function a receives to function b
}
a('asdf'); // this is okay

So if function a receives X number of parameters, each parameter is then passed into function b in the same order. So if a("1", "2"); , b("1", "2");, if a("1", 2, [3]); , b("1", 2, [3]);.

• javascript

Use Function.prototype.apply(thisArg[, argsArray]), like so:

b.apply(this, arguments);

Now, arguments is an array-like object that has some other properties (like callee) apart from its n-index properties. So, you probably ought to use Array.prototype.slice() to turn the object into a simple array of arguments (though either will work in modern environments).

b.apply(this, Array.prototype.slice.call(arguments));

_{See also: Function.prototype.call()}

why not pass them as a single object? advantages to using a single object as a parameter is that

• order is not necessary. unlike arguments where you have to know if it's the first, second, third in the receiving collection, in the object, they're just there. call them when you need them.
• you never worry about how many were passed. you can send one object containing a lot of properties - and you only pass one argument between the caller and callee

ofcourse, you have to test them out if they exist before using

function foo(data){
    data.param1; //is foo
    data.param2; //is bar
    data.param3; //is baz

    //send params to bar
    bar(data);
}

function bar(info){
    info.param1; //is foo
    info.param2; //is bar
    info.param3; //is baz
}

//call function foo and pass object with parameters
foo({
    param1 : 'foo',
    param2 : 'bar',
    param3 : 'baz'
})