Strip ruby string of a specific control character

This is pretty simple: how do I strip a ruby string of a special character? Here's the character: http://www.fileformat.info/info/unicode/char/2028/index.htm

And here's the string, with the two special characters between the period and the ending quote:

"Each of the levels requires logic, skill, and brute force to crush the enemy.  "

I've unsuccessfully tried this:

string.gsub!(/[\x00-\x1F\x7F]/, '')

and gsub("/\n/", "")

I'm using ruby 1.9.3p125

ruby

2012-04-05 00:02
by nnyby

gsub("/\n/", "") - Ascherer 2012-04-05 00:04

@Ascherer doesn't work : - nnyby 2012-04-05 00:05

\x1F ^_ (Unit separator, Information separator one) ...... go here http://donsnotes.com/tech/charsets/ascii.htm - zee 2016-01-25 05:04

I figured it out! .gsub(/\u2028/, '')

2012-04-05 00:09
by nnyby

i almost posted that first, but didnt know if ruby could do that hah - Ascherer 2012-04-05 00:19

If you were using version 1.8.6, you couldn't as it didn't have full Unicode support - Matt 2012-04-05 00:24

String#gsub will work, but is more general and less efficient at this than String#tr

irb> s ="Hello,\u2028 World; here's some ctrl [\1\2\3\4\5\6] chars"
=> "Hello,\u2028 World; here's some ctrl [\u0001\u0002\u0003\u0004\u0005\u0006] chars"

irb> s.tr("\u0000-\u001f\u007f\u2028",'')
=> "Hello, World; here's some ctrl [] chars"

require 'benchmark'
Benchmark.bm {|x|
  x.report('tr')   { 1_000_000.times{ s.tr("\u0000-\u001f\u007f\u2028",'') } }
  x.report('gsub') { 1_000_000.times{ s.gsub(/[\0-\x1f\x7f\u2028]/,'') } }
}

          user     system      total        real
tr    1.440000   0.000000   1.440000 (  1.448090)
gsub  4.110000   0.000000   4.110000 (  4.127100)

2012-04-05 02:33
by dbenhur