Is there a way to check if all the elements in an array are null in PHP?

For instance, I have an array array(null,null,null,null) - is there a way to check this scenario?

I am looking for a better way than just looping through the entire array and checking each element.

• php
• arrays

Another simple way of making this work is to use the max() function.

max(array( 3, 4, null, null  ) )      # is 4
max(array( null, null, null, null)    # is null

Thus you can issue a simple if( is_null(max($array)) ) { ... } call.

Try this:

$nulls = array(null,null,null,null,null,null,null,null);
var_dump(array_unique($nulls) === array(null)); // prints true

array_filter would work:

function checkIsset($val) {
    return isset($val);
}
$arr = array(null, null, null, ..., null);
$filteredArr = array_filter($arr, 'checkIsset');
if (count($filteredArr)) {
  //not all null
} else {
  //all null
}

or if (empty($filteredArr)) if you want the inverse.

You can use array_filter()

like this:

$nulls = array(null,null,null,null,null);
if(count(array_filter($nulls)) == 0){
  echo "all null (or false)";
}

Dunno what you expect in this array, but this lumps false in with the nulls...